Sum of digits of a number until the sum is reduced to 1 digit in c++

  • on February 4, 2019
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Today will discuss do while loop with an example, how to make a program in c++ by the do-while loop, do while loop in c++ with an example with explanation.
 Write a program in c++ to find the sum of digits of a number until the sum is reduced to 1 digit.
 For example
  The number is 538769.
  Then 5+3+8+7+6+9=38
            3+8=11
            11=2

Sum of digits of a number until the sum is reduced to 1 digit in c++ program

#include <iostream>
using namespace std;
int main()
{
long num,dig,sum;
cout<<“Enter a number :”<<endl;
cin>>num;
cout<<num<<endl;
do{
sum = 0;
while(num!=0)
{
dig=num%10;
sum+=dig;
num/=10;
}
cout<<“->”<<sum<<endl;
num=sum;
}while(num/10!=0);  /*while num is more than one digit*/
return 0;
}

Output: Enter The number 538769
            538769->38->11->2

Explanation :

      do{
/* 1: program code */
}while(num/10!=0);


                The Above Condition is not exit while num. is more than one digit.
     

/* 1: program code */
while(num!=0) 
{
dig=num%10;
sum+=dig;
num/=10;
}


     Here we use program code to find a sum of digit then the given program example is for “Sum of digits of a number until the sum is reduced to 1 digit”

So we find Your Program what we want. 

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