sum of digits and product of digits program in cpp

  • on February 4, 2019
  • Likes!
Hello Friends! Welcome to my blog
Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number of c++ programming language
The sum of digit of a number is added every digit of number
For example
a number is 5392 then sum of digit is 5+3+9+2=19
And product of digit of a number is multiplication of each digit
For Example
a number is 5392 then product of digit is 5*3*9*2=270
See programming Example:

c++ program find to sum of digits

      #include <iostream>
      using namespace std;
 int main(){
            int n ,d,sum=0;
            cout<<“enter The number”<<endl;
            cin>>n;
            while(n>0){
                d=n%10;
                sum=sum+d;
                n=n/10;
           }
      cout<<(“The sum of digit=”<<sum<<endl;
return 0;
     }


Output:
enter The number
185755
The sum of digit= 31

C++ program to find product of digits

    #include <iostream>
    using namespace std;
    int main(){
       int n ,d,pro=1;
       cout<<“enter The number”<<endl;
       cin>>n;
       while(n>0){
          d=n%10;
          pro=pro*d;
          n=n/10;
        }
        cout<<“The product of digit=” <<pro<<endl;
return 0;
    }

Output:
enter The number
5846
The product of digit= 960

I make this programming and hope you are like the post if are you like the post you can please comment and Share the post to reach more people.
If any doubt about this c++ programming code or input & output please comment below
If you have another question about c++ programming send an email by contacting us form is given on the page right side.
I am Try to Help in your Programming Language by Programming Shortcut
Please any query email programmingshortcut@gmail.com

Please comment your experience on this post,
Thank You!

Article Categories:
Programs in cpp

Leave a Reply

Your email address will not be published. Required fields are marked *