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Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number of c++ programming language

The sum of digit of a number is added every digit of number

For example

a number is 5392 then sum of digit is 5+3+9+2=19

And product of digit of a number is multiplication of each digit

For Example

a number is 5392 then product of digit is 5*3*9*2=270

See programming Example:

enter The number

185755

The sum of digit= 31

enter The number

5846

The product of digit= 960

Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number of c++ programming language

The sum of digit of a number is added every digit of number

For example

a number is 5392 then sum of digit is 5+3+9+2=19

And product of digit of a number is multiplication of each digit

For Example

a number is 5392 then product of digit is 5*3*9*2=270

See programming Example:

### c++ program find to sum of digits

#include <iostream>

using namespace std;

int main(){

int n ,d,sum=0;

cout<<“enter The number”<<endl;

cin>>n;

while(n>0){

d=n%10;

sum=sum+d;

n=n/10;

}

cout<<(“The sum of digit=”<<sum<<endl;

return 0;

}

using namespace std;

int main(){

int n ,d,sum=0;

cout<<“enter The number”<<endl;

cin>>n;

while(n>0){

d=n%10;

sum=sum+d;

n=n/10;

}

cout<<(“The sum of digit=”<<sum<<endl;

return 0;

}

**Output:**

enter The number

185755

The sum of digit= 31

### C++ program to find product of digits

#include <iostream>

using namespace std;

int main(){

int n ,d,pro=1;

cout<<“enter The number”<<endl;

cin>>n;

while(n>0){

d=n%10;

pro=pro*d;

n=n/10;

}

cout<<“The product of digit=” <<pro<<endl;

return 0;

}

using namespace std;

int main(){

int n ,d,pro=1;

cout<<“enter The number”<<endl;

cin>>n;

while(n>0){

d=n%10;

pro=pro*d;

n=n/10;

}

cout<<“The product of digit=” <<pro<<endl;

return 0;

}

**Output:**

enter The number

5846

The product of digit= 960

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