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Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number of c++ programming language
The sum of digit of a number is added every digit of number
For example
a number is 5392 then sum of digit is 5+3+9+2=19
And product of digit of a number is multiplication of each digit
For Example
a number is 5392 then product of digit is 5*3*9*2=270
See programming Example:
Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number of c++ programming language
The sum of digit of a number is added every digit of number
For example
a number is 5392 then sum of digit is 5+3+9+2=19
And product of digit of a number is multiplication of each digit
For Example
a number is 5392 then product of digit is 5*3*9*2=270
See programming Example:
c++ program find to sum of digits
#include <iostream>
using namespace std;
int main(){
int n ,d,sum=0;
cout<<“enter The number”<<endl;
cin>>n;
while(n>0){
d=n%10;
sum=sum+d;
n=n/10;
}
cout<<(“The sum of digit=”<<sum<<endl;
return 0;
}
using namespace std;
int main(){
int n ,d,sum=0;
cout<<“enter The number”<<endl;
cin>>n;
while(n>0){
d=n%10;
sum=sum+d;
n=n/10;
}
cout<<(“The sum of digit=”<<sum<<endl;
return 0;
}
Output:
enter The number
185755
The sum of digit= 31
enter The number
185755
The sum of digit= 31
C++ program to find product of digits
#include <iostream>
using namespace std;
int main(){
int n ,d,pro=1;
cout<<“enter The number”<<endl;
cin>>n;
while(n>0){
d=n%10;
pro=pro*d;
n=n/10;
}
cout<<“The product of digit=” <<pro<<endl;
return 0;
}
using namespace std;
int main(){
int n ,d,pro=1;
cout<<“enter The number”<<endl;
cin>>n;
while(n>0){
d=n%10;
pro=pro*d;
n=n/10;
}
cout<<“The product of digit=” <<pro<<endl;
return 0;
}
Output:
enter The number
5846
The product of digit= 960
enter The number
5846
The product of digit= 960
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