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Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number in c programming language

The sum of digit of a number is addition every digit of number

For example

a number is 5392 then sum of digit is 5+3+9+2=19

And product of digit of a number is multiplication of each digit

For Example

a number is 5392 then product of digit is 5*3*9*2=270

Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number in c programming language

The sum of digit of a number is addition every digit of number

For example

a number is 5392 then sum of digit is 5+3+9+2=19

And product of digit of a number is multiplication of each digit

For Example

a number is 5392 then product of digit is 5*3*9*2=270

**See programming Example:**### c program find to sum of digits

#include<stdio.h>

#include<conio.h>

void main(){

int n ,d,sum=0;

clrscr();

printf(“enter The number”);

scanf(“%d”,&n);

while(n>0){

d=n%10;

sum=sum+d;

n=n/10;

}

printf(“The sum of digit= %d”,sum);

getch();

}

#include<conio.h>

void main(){

int n ,d,sum=0;

clrscr();

printf(“enter The number”);

scanf(“%d”,&n);

while(n>0){

d=n%10;

sum=sum+d;

n=n/10;

}

printf(“The sum of digit= %d”,sum);

getch();

}

**Output:**

*enter The number*

*185755*

*The sum of digit= 31*

### C program to find product of digits

#include<stdio.h>

#include<conio.h>

void main(){

int n ,d,pro=1;

clrscr();

printf(“enter The number”);

scanf(“%d”,&n);

while(n>0){

d=n%10;

pro=pro+d;

n=n/10;

}

printf(“The product of digit= %d”,pro);

getch();

}

#include<conio.h>

void main(){

int n ,d,pro=1;

clrscr();

printf(“enter The number”);

scanf(“%d”,&n);

while(n>0){

d=n%10;

pro=pro+d;

n=n/10;

}

printf(“The product of digit= %d”,pro);

getch();

}

**Output:**

*enter The number*

*5846*

*The product of digit= 960*

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