sum and product of digit program in java

  • on February 4, 2019
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Hello Friends! Welcome to my blog
Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number in java programming language
The sum of digit of a number is added every digit of number
For example
a number is 8554 then sum of digit is 8+5+5+4=22
And product of digit of a number is multiplication of each digit
For Example
a number is 4581 then product of digit is 4*5*8*1=160
See programming Example:

java program find to sum of digits

import java.util.Scanner;
public class sum_of_digit {
public static void main(String[] args) {
int n, d, s = 0;
Scanner in = new Scanner(System.in);
System.out.println(“enter the number”);
n = in.nextInt();

while (n > 0) {
d = n % 10;
s = s + d;
n = n / 10;
}
System.out.println(“The sum of digit 458″+s);
}
}

Output:
enter the number
8554
The sum of digit 22

java program to find product of digits

import java.util.Scanner;
public class product_of_digit {
public static void main(String[] args) {
int n, d, p = 1;
Scanner in = new Scanner(System.in);
System.out.println(“enter the number”);
n = in.nextInt();

while (n > 0) {
d = n % 10;
p = p * d;
n = n / 10;
}
System.out.println(“The product of digit “+ p);
}
}


Output:
enter the number
4581
The product of digit 160

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