Find grade of a student according to their percentage in c programming

  • on February 4, 2019
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Today we run C programming to find out the grade of a student when the marks of 6 subjects are given.
The method of assigning grade is –
percentage>=85 grade=A
percentage<85  and percentage>=70 grade=B
percentage<70  and percentage>=55 grade=C
percentage<55  and percentage>=40 grade=D
percentage<40 grade=E

This c language programming is free all type of errors like the compiler and runtime errors and this programming is tested to compile and then run the program code.
Here is only programming code with the output. This programming output is customized to understand easily.

Find grade of a student according to their percentage in c programming

#include<stdio.h>
#include<conio.h>
void main()
{
float m1,m2,m3,m4,m5,m6,total,per;
char grade, name;
printf(“Please Enter the Student Name:”);
scanf(“%c”,&name);
printf(“Enter all subjects marks of %c: “,name);
scanf(“t%ft%ft%ft%ft%ft%f”,&m1,&m2,&m3,&m4,&m5,&m6);
printf(“n”);
//Calculate the percentage of all Marks
total=m1+m2+m3+m4+m5+m6;
per=total/6;
//Condtion Check for to find the grade of
if(per>33){
if(per>=85){
grade=’A’;
}
else if(per>=70){
grade=’B’;
}
else if(per>=55){
grade=’C’;
}
else if(per>=40){
grade=’D’;
}
else {
grade=’E’;
}
printf(“%c passed with %c Grade and %fn”,name,per,grade);
}
else{
printf(“%c is Fail in the Examnation ” name);
}
getch();
}

Output:
     Please Enter the Student Name: Abcd
     Enter all subjects marks of Abcd: 75
         74
45
89
100
99
     Abcd passed with B Grade and 80.33333333333333%

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Article Categories:
Programs in c

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