Find a year is leap year or not in java

  • on February 4, 2019
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Java programming to find the year is a leap year or not that year entered by the user?
This Java language programming is free all type of errors like the compiler and runtime errors and this programming is tested to compile and then run the program code.
Here is only programming code with the output. This programming output is customized to understand easily.

Program to find a year is leap year or not in java

import java.util.Scanner;

class test1 {

    int year;

    public void show_laep_year(int year) {
        if (year % 100 != 0) {
            if (year % 4 == 0) {
                System.out.println(“The year “+ year+ ” is a Leap Year”);
            }
            else {
                System.out.println(“The year “+ year+ ” is not a Leap Year”);
            }
        } else {
            if (year % 400 == 0) {
                System.out.println(“The year “+ year+ ” is a Leap Year”);
            }
            else {
                System.out.println(“The year “+ year+ ” is not a Leap Year”);
            }
        }
    }
}
public class leapyear {

    public static void main(String[] args) {
        Scanner c = new Scanner(System.in);
        test1 o = new test1();
        System.out.print(“Please Enter a Year: “);
        o.year = c.nextInt();
        o.show_laep_year(o.year);
    }
}

Output:
     Please Enter a Year: 2016
     The year 2016 is a Leap Year

     Please Enter a Year: 2015
     The year 2015 is not a Leap Year

Note: This Java programming is run two time


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