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Monday, February 4, 2019

sum of digits and product of digits program in cpp

Hello Friends! Welcome to my blog
Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number of c++ programming language
The sum of digit of a number is added every digit of number
For example
a number is 5392 then sum of digit is 5+3+9+2=19
And product of digit of a number is multiplication of each digit
For Example
a number is 5392 then product of digit is 5*3*9*2=270
See programming Example:

c++ program find to sum of digits



      #include
      using namespace std;
 int main(){
            int n ,d,sum=0;
            cout<<"enter The number"<             cin>>n;
            while(n>0){
                d=n%10;
                sum=sum+d;
                n=n/10;
           }
      cout<<("The sum of digit="< return 0;
     }


Output:
enter The number
185755
The sum of digit= 31


C++ program to find product of digits


    #include
    using namespace std;
    int main(){
       int n ,d,pro=1;
       cout<<"enter The number"<        cin>>n;
       while(n>0){
          d=n%10;
          pro=pro*d;
          n=n/10;
        }
        cout<<"The product of digit=" < return 0;
    }

Output:
enter The number
5846
The product of digit= 960


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