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Monday, February 4, 2019

sum and product of digit program in java

Hello Friends! Welcome to my blog
Today We will Discus about how to calculate sum of digit and product of digit using while loop of a number in java programming language
The sum of digit of a number is added every digit of number
For example
a number is 8554 then sum of digit is 8+5+5+4=22
And product of digit of a number is multiplication of each digit
For Example
a number is 4581 then product of digit is 4*5*8*1=160
See programming Example:


java program find to sum of digits




import java.util.Scanner;
public class sum_of_digit {
public static void main(String[] args) {
int n, d, s = 0;
Scanner in = new Scanner(System.in);
System.out.println("enter the number");
n = in.nextInt();

while (n > 0) {
d = n % 10;
s = s + d;
n = n / 10;
}
System.out.println("The sum of digit 458"+s);
}
}


Output:
enter the number
8554
The sum of digit 22


java program to find product of digits



import java.util.Scanner;
public class product_of_digit {
public static void main(String[] args) {
int n, d, p = 1;
Scanner in = new Scanner(System.in);
System.out.println("enter the number");
n = in.nextInt();

while (n > 0) {
d = n % 10;
p = p * d;
n = n / 10;
}
System.out.println("The product of digit "+ p);
}
}


Output:
enter the number
4581
The product of digit 160

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